Electrical cable sizing: ampacity, correction factors and voltage drop per NBR 5410
Cable sizing per NBR 5410 picks the smallest commercial cross-section whose current-carrying capacity, already corrected for temperature and grouping, withstands the design current — while keeping voltage drop within the limit.
When to use
Use it whenever you need to specify the cross-section of a low-voltage cable in an industrial electrical project: switchboard feeders (main and distribution boards), motor branch circuits in MCCs, transformer primary and secondary feeders, lighting and socket-outlet circuits. Sizing is the step that links the load current to the physical conductor size — it sets the copper or aluminum cross-section, the cable notation (phase, neutral, earth) and checks that the voltage drop to the load is acceptable. It is also the tool to audit existing installations that overheat, or where motors start poorly due to undervoltage, almost always from an undersized section or an installation method more severe than assumed.
What cable sizing is
Sizing a cable is not picking a size from the load’s rated current: it is finding the smallest commercial cross-section that satisfies two independent criteria at once — current-carrying capacity (ampacity) and voltage drop — within the circuit’s real installation method. The cable must carry the current without the insulation exceeding its allowable temperature and, at the same time, deliver to the load a voltage within a narrow band. The final size is the larger of the two requirements.
The most common field mistake is to size by the raw rated current, skip the correction factors, and later find cables overheating in a crowded conduit or motors starting poorly from undervoltage. The cause is almost always the same: the tabulated ampacity was treated as if it held in the real installation, when it holds in a far more favorable reference condition.
The design current
It all starts with the design current Ib, the current the load actually draws. For a three-phase load defined by active power:
Ib = P·1000 / (√3·V·PF·η)
where P is the power [kW], V the line voltage [V], PF the power factor and η the efficiency. For single-phase, the √3 leaves the denominator and V/√3 is used. When the load is defined by apparent power (kVA) — the typical case for transformers — S enters directly, without PF·η, because the efficiency is already embedded: Ib = S·1000/(√3·V).
The corrected current: why the table ampacity is not enough
The tabulated current-carrying capacity (Iz) applies to a reference condition: 30 °C ambient in air and a single circuit. In the real installation, two things degrade that capacity:
- Ambient temperature above the reference reduces the insulation’s thermal margin — factor Ft.
- Grouping of several circuits in the same conduit, raceway or tray makes the cables heat each other — factor Fa.
In addition, some loads require the conductor to be oversized: a motor at 125% of the full-load current (Imult = 1.25), a capacitor at 135% (IEC 60831). Putting it together, the required ampacity is:
Ibc = (Ib · Imult) / (Ft · Fa)
Since Ft and Fa are below 1, the division raises the requirement. It is this corrected current — not the bare Ib — that must be compared against the ampacity table.
Selecting the section by ampacity
With Ibc in hand, the section is the smallest commercial size whose tabulated ampacity, in the chosen installation method, exceeds the corrected current per circuit (Ibc divided by the number of parallel cables per phase):
S = smallest section with Iz_table(S, method) ≥ Ibc / n_cables
The ampacity table depends on the NBR 5410 reference method (Table 33): A1 and A2 (conduit in a thermally insulating wall, the most severe), B1 and B2 (surface conduit), C (on a wall or unperforated tray), D (buried in ducts), E and F (tray or perforated raceway, the most favorable). The same 70 mm² copper cable carries 149 A in conduit (B2) and 216 A on a perforated tray (F) — about 45% more — because the tray in air dissipates heat far better than the conduit. Getting the method wrong is getting the size wrong.
Material and insulation change the table
The base tables are for copper, EPR/XLPE 90 °C insulation. Two physical adjustments are applied:
- Aluminum: resistivity ≈ 1.649 times that of copper → higher resistance (×1.649) and lower ampacity (×1/√1.649 ≈ 0.779). Aluminum always needs a larger size and produces more voltage drop.
- PVC 70 °C: smaller thermal margin → ampacity derated by √[(70−30)/(90−30)] ≈ 0.816 relative to EPR 90 °C; the table resistance drops slightly (×0.938).
Treating aluminum as copper, or PVC as EPR, is a direct undersize.
The voltage-drop check
Ampacity guarantees the cable does not overheat; voltage drop guarantees the load receives enough voltage. For three-phase:
ΔV% = 100·√3·Ib·L·(R·cosφ + X·sinφ) / V
where L is the length [km], R = Rac and X = XL [Ω/km] are the section’s resistance and reactance, cosφ = PF and sinφ = √(1−PF²). For single-phase, √3 becomes 2 and the reference voltage is V/√3; with n parallel cables, R and X are divided by n. The usual limit is 3% for general loads and 4% for motors (which tolerate more because of starting), per NBR 5410 (6.2.7).
On short circuits ampacity governs; on long circuits the drop grows linearly with length and may force one or more sizes up just to keep the load voltage within the limit — even with ample ampacity.
Coordination with the protection
The chosen section does not stand alone: it must be protected by the breaker. NBR 5410 (6.3.4.1) requires:
Ib ≤ In ≤ Iz and I2 ≤ 1.45·Iz
where In is the breaker rated current, Iz = Iz_table·Ft·Fa·n_cables is the cable capacity already corrected for the installation (not the raw table value, which would overstate the protection) and I2 = 1.45·In is the conventional tripping current (IEC 60898/60947). For a motor, overload is handled by the thermal relay of the motor protector and the breaker only covers the short circuit; in that case Ib ≤ Iz suffices.
Cable composition: phase, neutral and earth
Sizing also delivers the cable notation (KxLc#Ymm²: K cables, L conductors per cable, Y the size):
- Neutral: only the single-phase circuit has a neutral, carrying the full current (equal to the phase). A balanced three-phase circuit carries no sized neutral.
- Protective conductor (PE): follows Table 58 — PE = phase up to 16 mm², 16 mm² between 16 and 35 mm², and half the phase above 35 mm².
- When the neutral or PE share the same size as the phase, they merge into the same conductor group; if smaller, they become separate single-core cables.
Practical design considerations
- Do not skip the correction factors: Ft and Fa are the difference between a cable that lasts and one that cooks its insulation.
- Always check ampacity AND drop: the final size is the larger of the two requirements, and on long runs the drop usually wins.
- Get the installation method right: it sets which table column applies — and the ampacity changes nearly 50% between conduit and tray.
- Coordinate with the protection: Ib ≤ In ≤ Iz closes the loop; without it, the breaker does not protect the cable.
Following this chain — design current, correction factors, selection by ampacity, voltage-drop check and coordination with the protection — yields a cable sizing that is numerically rigorous and stands up to installation reality.
Formulas and fundamentals
Ib = P·1000 / (√3·V·PF·η) [three-phase] Current the load actually draws. P is the active power [kW], V the line voltage [V], PF the power factor [dimensionless] and η the efficiency [dimensionless]. For single-phase, V/√3 is used in the denominator (no √3), and for an apparent-power load (kVA) S enters directly, without PF·η: Ib = S·1000/(√3·V).
Ibc = (Ib · Imult) / (Ft · Fa) Current-carrying capacity the cable must have in the real installation. Imult is the load multiplier (1.25 for a motor, 1 for resistive, 1.35 for a capacitor); Ft is the temperature correction factor and Fa the grouping factor. Dividing by Ft·Fa < 1 raises the requirement, because the cable carries less when hot or grouped.
S = smallest section with Iz_table(S, method) ≥ Ibc / n_cables Commercial-size selection: the smallest cross-section whose tabulated current-carrying capacity Iz, in the chosen installation method, withstands the corrected current per circuit (Ibc divided by the number of parallel cables per phase). The table depends on the reference method (A1…F) and on the material/insulation.
ΔV% = 100·√3·Ib·L·(R·cosφ + X·sinφ) / V Percentage drop along the cable. L is the length [km], R the resistance Rac [Ω/km] and X the reactance XL [Ω/km] of the section, cosφ = PF and sinφ = √(1−PF²). For single-phase the √3 factor becomes 2 and V/√3 is used. With n parallel cables, R and X are divided by n.
Ib ≤ In ≤ Iz and I2 ≤ 1.45·Iz NBR 5410 (6.3.4.1) criterion. In is the breaker rated current, Iz = Iz_table·Ft·Fa·n_cables the in-situ cable capacity and I2 = 1.45·In the conventional tripping current (IEC 60898/60947). For a motor, overload is handled by the relay and only Ib ≤ Iz is checked.
Standards & methods
- ABNT NBR 5410 — Low-voltage electrical installations
- IEC 60364-5-52 — Selection and erection of wiring systems (current-carrying capacity)
- NBR 5410 Table 33 — reference installation methods (A1, A2, B1, B2, C, D, E, F)
- NBR 5410 Table 40 — ambient temperature correction factors
- NBR 5410 Table 42 — circuit grouping factors
- NBR 5410 Tables 48 and 58 — neutral and protective (PE) conductor cross-sections
- IEC 60898-1 / IEC 60947-2 — circuit breakers (MCB / MCCB / ACB / MPCB)
Typical reference values
| Quantity | Typical range | Note |
|---|---|---|
| Default temperature factor (Ft) | 0.87 (in air) · 0.89 (buried) | Fixed spreadsheet values; if the ambient temperature is given, derived from Table 40. |
| Grouping factor (Fa) by method | 0.60 to 0.78 | 0.60 (A/B/D), 0.70 (C), 0.78 (E/F tray). Per Table 42, 2 circuits = 0.80; 6 = 0.57. |
| Load multiplier (Imult) | 1.00 to 1.35 | Motor 1.25 (125% of FLC); resistive/lighting 1.00; capacitor 1.35 (IEC 60831). |
| Voltage-drop limit | 3 % (general) · 4 % (motor) | Project convention over NBR 5410 6.2.7; motors tolerate more during starting. |
| Copper Rac resistance | 8.87 Ω/km (2.5 mm²) to 0.08 Ω/km (300 mm²) | Aluminum ≈ Cu × 1.649. PVC 70 °C uses slightly lower ρ (×0.938). |
| Material and insulation derating | Al ≈ Cu × 0.779 · PVC ≈ EPR × 0.816 | Aluminum and PVC 70 °C ampacities below copper/EPR 90 °C (same geometry). |
Worked example
Feeder cable for a 30 kW three-phase motor
Inputs
- Motor power
- P = 30 kW
- Line voltage
- V = 380 V
- Power factor / efficiency
- PF = 0.85 · η = 92 % (η)
- Installation method
- B1 (surface conduit) —
- Material / insulation
- Copper · EPR 90 °C —
- Circuit length
- L = 60 m
Results
- Design current
- Ib ≈ 58.3 A
- Required (corrected) ampacity
- Ibc ≈ 139.6 A
- Adopted commercial section
- S = 70 mm²
- In-situ capacity (Iz)
- Iz ≈ 89.3 A
- Voltage drop
- ΔV ≈ 0.52 %
The design current is Ib = 30000/(√3·380·0.85·0.92) ≈ 58.3 A. Being a motor, it is multiplied by 1.25 and corrected by Ft·Fa = 0.87·0.60 = 0.522: Ibc = 58.3·1.25/0.522 ≈ 139.6 A. The smallest copper EPR 90 °C section whose B1 ampacity (171 A at 70 mm²; 134 A at 50 mm²) covers 139.6 A is 70 mm². The voltage drop with Rac = 0.32 Ω/km, XL = 0.10 Ω/km, sinφ = 0.527 and L = 0.06 km is ΔV = 100·√3·58.3·0.06·(0.32·0.85 + 0.10·0.527)/380 ≈ 0.52%, well below the 4% motor limit. The in-situ capacity Iz = 171·0.87·0.60 ≈ 89.3 A exceeds Ib, closing the coordination. The chosen size is governed by ampacity — not by voltage drop, given the short distance.
Common mistakes
- Sizing by the rated current without the multiplier: for a motor the conductor must withstand 125% of the full-load current, not just the FLC.
- Forgetting the correction factors: without dividing by Ft·Fa, the section is undersized and the cable overheats past the insulation rating on a hot day or in a crowded conduit.
- Checking only ampacity and ignoring voltage drop: on long cables the drop governs the size, even with ample ampacity.
- Treating aluminum as copper: Al has ~65% higher resistance and ~22% lower ampacity; copying the copper table is a dangerous undersize.
- Using the wrong installation method: swapping B1 (conduit) for E/F (tray) inflates the tabulated ampacity and yields a smaller section than the real installation can carry.
- Not coordinating with the protection: the section must satisfy Ib ≤ In ≤ Iz, otherwise the breaker does not protect the cable against overload.
Frequently asked questions
Why is the table ampacity not the current the cable carries in the installation?
The tabulated capacity Iz applies to a reference condition (30 °C in air, one circuit). In the real installation, a higher ambient temperature and grouped cables reduce heat dissipation. So the in-situ ampacity Iz = Iz_table·Ft·Fa·n_cables is applied, and sizing requires that this corrected capacity exceed the design current.
When does voltage drop govern the size instead of ampacity?
On long circuits. Ampacity depends only on the current and the installation, but the drop grows linearly with length. Beyond a few tens of meters, the section that meets ampacity may give a drop above 3–4%, forcing one or more sizes up just to keep the load voltage within the limit.
How does the method choose between multicore and single-core cables?
Multicore is preferred (one cable carrying all phases). When the computed section exceeds the largest practical multicore (240 mm²), the method switches to single-core cables, paralleling several per phase until each conductor falls below the practical ceiling. The user chooses only the physical installation; the formation and number of cables are decided automatically.
Why does aluminum need a larger section than copper?
Aluminum has about 1.65 times the resistivity of copper. For the same geometry and temperature limit, that lowers ampacity by ~22% (∝ 1/√ρ) and raises resistance by ~65%. Sizing corrects the copper table by these factors, yielding a larger size — and a larger voltage drop for the same length.
What is coordination between the breaker and the cable?
It ensures the protection actually protects the conductor. NBR 5410 requires Ib ≤ In ≤ Iz (the breaker rated current sits between the design current and the cable capacity) and I2 ≤ 1.45·Iz. For a motor, overload is handled by the thermal relay and the breaker only covers the short circuit, so Ib ≤ Iz is enough.
How do the neutral and protective conductor come in?
Only the single-phase circuit has a neutral (carrying the full current, equal to the phase). The protective conductor (PE) follows Table 58: PE = phase up to 16 mm², 16 mm² between 16 and 35, and half the phase above 35. When the neutral or PE share the phase size, they merge into the same group in the KxLc#Ymm² notation.
Glossary
- Ampacity (current-carrying capacity)
- Maximum current a conductor carries in steady state without exceeding the allowable insulation temperature; tabulated by cross-section, installation method and material/insulation.
- Design current (Ib)
- Current the load draws in operation, computed from power, voltage, power factor and efficiency.
- Temperature correction factor (Ft)
- Multiplier that reduces ampacity when the ambient temperature exceeds the reference (30 °C in air); tabulated by insulation (PVC 70 °C / EPR 90 °C) in Table 40.
- Grouping factor (Fa)
- Multiplier that reduces ampacity when several circuits share the same conduit, raceway or tray, due to mutual heating (Table 42).
- Reference method
- Cable installation arrangement (A1 to F in NBR 5410 Table 33) that sets the ampacity table — from conduit in an insulating wall (most severe) to tray in free air (most favorable).
- Voltage drop (ΔV)
- Voltage lost between the source and the load, as a percentage of nominal voltage, a function of the current, length and cable impedance (R, X).
- In-situ Iz
- Real current-carrying capacity of the cable in the installation: the tabulated ampacity corrected by Ft, Fa and the number of parallel cables.
- Protection × conductor coordination
- Rule matching the breaker to the cable (Ib ≤ In ≤ Iz and I2 ≤ 1.45·Iz) so the protection acts before the conductor suffers thermal damage.